Re: horse weight -- corrected formula

["Glenn Foster" <gfoste19@idt.net>]

Well, I guess I can just toss the page in the logbook. 

From "The Horse", second edition, 1990
by Evans, Borton, Hintz, and Van Eck, 
W.H. Freeman and Co.

(using, again ^2 and ^3 to represent superscripted powers
H is heartgirth in inches
L is length in inches
W is weight in lbs

p. 296 (general formula)

W = H ^2  x L  / 241.3

(which I believe is what I posted before).  

However,  from p. 140 , the following should be correct and my transcription
errors obvious:

(Males)
W = ( .14475 x H )^3

(Females)
W = (.14341 x H)^3

(Colts to 5 yo)
W = (.1387 x H + 0.4)^3

(Fillies to 5 yo)
W = (.1382 x H + 0.344)^3

For your mare I would then get
.14341 x 71 = 10.18211
10.18211 x 10.18211 x 10.18211 = 1055 lb

Gayle Ecker's  constant (330)  is for sure going to be based on 
more recent and more thorough research than my somewhat 
dated text: 

71*71*59 / 330 = 901 lb

-----Original Message-----
From: Dorothy Foster <hitech@sunset.net>
To: gfoste19@idt.net <gfoste19@idt.net>
Date: Wednesday, June 24, 1998 4:48 PM
Subject: horse weight


>Hi Glenn
>My math isn't too swift, but I really think there's something wrong with
>your formulae. My small Arab mare should weigh several tons according to
>the mare formula:
>
>Heartgirth 71" Length 59"
>
>71 x 71 x 71 = 357911 x 1.4341 = 513280????? 
>
>The general formula is still way off:
>
>W=HxHxL/241.3 = 71 x 71 x 59 / 241.3 = 1232.5694. There is no way she
>weighs that much...more like 900 soaking wet. What am I doing wrong??????
>
>Dorothy Foster (my husband is from MI too, but Traverse City area)
>Hi Tech Tack
>Oroville, CA
>